2x^2-16x+30=2(x-3)(x-5)

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Solution for 2x^2-16x+30=2(x-3)(x-5) equation: 



2x^2-16x+30=2(x-3)(x-5)

We move all terms to the left:

2x^2-16x+30-(2(x-3)(x-5))=0

We multiply parentheses ..

2x^2-(2(+x^2-5x-3x+15))-16x+30=0



We calculate terms in parentheses: -(2(+x^2-5x-3x+15)), so:

2(+x^2-5x-3x+15)

We multiply parentheses

2x^2-10x-6x+30

We add all the numbers together, and all the variables

2x^2-16x+30

Back to the equation:

-(2x^2-16x+30)



We add all the numbers together, and all the variables

2x^2-16x-(2x^2-16x+30)+30=0

We get rid of parentheses

2x^2-2x^2-16x+16x-30+30=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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